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2.A trolley, while going down aninclined plane, has anacceleration of 2 cm s-2. What willbe its velocity 3 s after the start?

Answer»

The "velocity of the trolley" at 3 s is 0.06 m/s .Given data:ACCELERATION, a = 2 cm/s^2 = 0.02 m/s^2To find:Velocity after 3 s = ?SOLUTION:The trolley is on the inclined plane,Thereby, the FIRST equation of MOTION is to be applied to calculate velocity after 3 sec.Therefore, we have,t = 3 secu = 0 a=2 \ \mathrm{cm} / \mathrm{s}^{2}=0.02 \ \mathrm{m} / \mathrm{s}^{2}a=2 cm/s 2 =0.02 m/s 2 v=u+a tv=u+atv=0+(0.02 \times 3)v=0+(0.02×3)\Rightarrow v=0.06 \ m / s⇒v=0.06 m/sExplanation:hope it will help u and mark me as brilliant



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