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2-Bromopentane is treated with alcoholic KOH solution. Whatt will be the major product formed in this reaction and what is the type of elimination called?

Answer» <html><body><p>Pent-1-ene, `beta`-Elimination&lt;<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>&gt;Pent-2-ene, `beta`-elimination<br/>Pent-1-ene, Nucleophilic substitution<br/>Pent-2-ene, Nucleophilic substitution.</p>Solution :`underset("2-Bromopentane")(CH_(3)CH_(2)-CH_(2)-) underset(Br)underset(|)(C)H-CH_(3) underset(-<a href="https://interviewquestions.tuteehub.com/tag/hbr-479388" style="font-weight:bold;" target="_blank" title="Click to know more about HBR">HBR</a>" "(beta-"elimination"))overset("alc. <a href="https://interviewquestions.tuteehub.com/tag/koh-528424" style="font-weight:bold;" target="_blank" title="Click to know more about KOH">KOH</a>")to CH_(3)-underset("2-Pentene")(CH_(2)-<a href="https://interviewquestions.tuteehub.com/tag/ch-913588" style="font-weight:bold;" target="_blank" title="Click to know more about CH">CH</a>=CH-CH_(3))`.</body></html>


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