1.

2. चांद shatam का मान जारी गए ।

Answer»

SinA=15/17 and cosB=12/13Using, sin²A+cos²A=1 we get,cos²A=1-sin²A=1-225/289=(289-225)/289=64/289cosA=8/17 (neglecting the neggative sign since A,B are positive acute angles)sin²B=1-cos²B=1-144/169=(169-144)/169=25/169sinB=5/13(neglecting the neggative sign since A,B are positive acute angles)sin(A+B)=sinAcosB+cosAsinB=15/17×12/13+8/17×5/13=180/221+40/221=220/221cos(A-B)=cosAcosB-sinAsinB=8/17×12/13-15/17×5/13=96/221-75/221=21/221tanA=sinA/cosA=(15/17)/(8/17)=15/8 andtanB=sinB/cosB=(5/13)/(12/13)=5/12 tan(A+B)=(tanA+tanB)/(1-tanAtanB)=(15/8+5/12)/(1-15/8×5/12)=[(45+10)/24]/[(96-75)/96]=(55/24)/(21/96)= 55/24×96/21=210/21=10

15/8 is the correct answer

15/8 is correct answer



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