1.

2 g each of the solutes A and B ( mol mass of A gt B) are dissolved separately in 20 g each of the same solvent C. Which will show gr eater lowering of vapour pressure and why ?

Answer»

SOLUTION :`"for dilute solutions, "(p^(@)-p_(s))/(p^(@))=(w_(2)M_(1))/(w_(1)M_(2)) or (DELTAP)/(p^(@))=(w_(2)M_(1))/(w_(1)M_(2))`
`"For same SOLVENT, "p^(@)=" constant, "M_(1)="constant. Also, given that "w_(2)=w_(A)=w_(B)=2g, w_(1)=w_(C)=20 g`
Hence, `(Deltap_(A))/(Deltap_(B))=(M_(B))/(M_(A))." As "M_(A) gt M_(B)`, therefore, `Deltap_(B) gt Deltap_(A)`, i.e., B will show greater lowering of vapour pressure.


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