2.How much work is done in moving a chargeof 3.0 coulbmb from a point

1.	2.How much work is done in moving a chargeof 3.0 coulbmb from a point at 120 V to apoint at 200 V ?. (Ans. 240 Joule)
Answer» V =V2-V1 = 80V Q= 3C W = V×Q = 80 × 3 = 240J we knew that voltage = work done/charge work done = ∆voltagecharge =( 200-120) 3 =240 joules. plz accept as best Plz like my answer Plz accepted as best Plz Q(charge)=3CV(potential difference)=200-120=80vwe know that V=W/Qso,80=W/3W=80*3W=240Jhope this answer helps you. 240Joule is correct answer voltage = work done/chargework done = ∆voltage ✖ charge = ( 200-120) ✖ 3 = 240 joules. v=v2-v1 =80v q= 3c w = v×q =80 × 3 = 240 j work done=charge×voltage=3×(200-120)=3×80=240 joules

2.How much work is done in moving a chargeof 3.0 coulbmb from a point at 120 V to apoint at 200 V ?. (Ans. 240 Joule)

Answer»

V =V2-V1 = 80V Q= 3C W = V×Q = 80 × 3 = 240J

we knew that

voltage = work done/charge

work done = ∆voltage*charge

=( 200-120)* 3

=240 joules.

plz accept as best Plz like my answer Plz accepted as best Plz

Q(charge)=3CV(potential difference)=200-120=80vwe know that V=W/Qso,80=W/3W=80*3W=240Jhope this answer helps you.

240Joule is correct answer

voltage = work done/chargework done = ∆voltage ✖ charge = ( 200-120) ✖ 3 = 240 joules.

v=v2-v1 =80v q= 3c w = v×q =80 × 3 = 240 j

work done=charge×voltage=3×(200-120)=3×80=240 joules