1.

(2) If the value of tarn-s , then the value of sec θ is . . . . . . .

Answer»

We know tan² + 1 = sec²

So,

given tan = 3/5

(3/5)² + 1

9/25 + 1 = 34/25

So, sec² = 34/25

sec = √34/5



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