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2. In Fig. 8.13, find tan P-cot R.12 cm13 cmQi |
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Answer» using Pythagoras law we got QR² = PR² - PQ² => QR = √ PR² - PQ² => QP = √ ( 13 )² - ( 12 )² => QP = √ 169 - 144 => QP = √25 => QP = 5 .°. tan P = QR/PQ tan P = 5/12 and Cot R = QR/PQ Cot R = 5/12 now tan P - Cot R = 5/12 - 5/12 = 0 |
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