2. In Fig., ifLA= (2x+10°,LB=(x+20)",10)°, find the<C = (y-50° and

1.	2. In Fig., ifLA= (2x+10°,LB=(x+20)",10)°, find the<C = (y-50° and <D = (y-values of x and y.10)Aký (2x(+1050)0%(x+20)
Answer» sum of opposite angle of a cyclic quadrilateral is = 180° so, y-10 +x+20 = 180=> x+y = 170 and 2x+y = 180-10+ 50 = 220 now subtracting 1 from 2 => 2x -x = 220 -170 = 50=> x = 50/2 = 25° and y = 170-25 = 145°

2. In Fig., ifLA= (2x+10°,LB=(x+20)",10)°, find the<C = (y-50° and <D = (y-values of x and y.10)Aký (2x(+1050)0%(x+20)

Answer»

sum of opposite angle of a cyclic quadrilateral is = 180°

so, y-10 +x+20 = 180=> x+y = 170

and 2x+y = 180-10+ 50 = 220

now subtracting 1 from 2

=> 2x -x = 220 -170 = 50=> x = 50/2 = 25°

and y = 170-25 = 145°