1.

2 Kg of water of 60^(@)C is mixed with 1 kg of water at 30^(@)C kept in a vessel of heat capacity "220 J K"^(-1). The specific heat of water is "4200 J Kg"^(-1)K^(-1). Then the final temperature is nearly.

Answer»

(a) `35^(@)C`
(b) `45^(@)C`
(c) `55^(@)C`
(d) `50^(@)C`

Solution :ACCORDING to the PRINCIPLE of calorimetry,
`2xx4200xx(60-THETA)=(14200+200)(theta-30)RARR theta =50^(@)C`


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