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2 mi Pare ngents to the circle with centre O such that LAPB S0P ind theB. |
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Answer» Since OA is perpendicular to PA and also, OB is perpendicular to PB ∠APB + ∠AOB = 180° 50°+ ∠AOB = 180° ∠AOB = 180° – 50° = 130° In △AOB, OA = OB = radii of same circle ∠OAB = ∠OBA = x ( say ) Again, ∠OAB + ∠OBA + ∠AOB = 180° x +x + 130° = 180° 2x = 180° – 130° = 50° X = 25° Hence, ∠OAB =25° |
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