2 tan 70∘cot 20∘−tan 33∘cot 57∘−√2 cos 45∘= _____

1.	2 tan 70∘cot 20∘−tan 33∘cot 57∘−√2 cos 45∘= _____
Answer» $2 \frac{t a n 70^{\circ}}{c o t 20^{\circ}} - \frac{t a n 33^{\circ}}{c o t 57^{\circ}} - \sqrt{2} c o s 45^{\circ} =$ _____

Discussion