InterviewSolution
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InterviewSolution
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2, The rate of reaction between two reactants A andB decreases by a factor of 4 if the concentrationof reactant B is doubled. The order of this reactionwith respect to reactant B is s1)-1 (2)-2 (3)1 |
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Answer» XA + yB ----------> ProductRate= k[A]^x.[B]^y .........(i)When conc. of B is doubled, Rate/4 = k[A]^x.[2B]^y...........(ii)Equation (i)/(ii)4=1/2^y⇒2^y = 1/2²⇒y=-2 with respect to B |
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