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2.Writetheprincipalvalucofcosec(D) |
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Answer» Let cosec-¹(2) = ∅ where ∅ is the principal branch of cosec-¹(2) therefore cosec∅ = 2 since the range of principal value of branch of cosec-¹x is [+π/2,π/2] -{0} therefore -π/2≤∅≤π/2, ∅≠0 Now cosec∅ = 2 = cosecπ/6 thus ∅ = π/6 as cosecπ/6 = 2 and π/6 € [-π/2,π/2]-{0} |
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