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2 x - 1 \leq x ^ { 2 } + 3 \leq x - 1 |
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Answer» The given inequality is 2x-1≤x²+3≤x-1 => 2x-1-3 ≤x²≤x-1-3=> 2x-4 ≤ x²≤ x-4 since 2x-4 will be > 0 oy when x > 2 , and at x > 2 , x² will always be greater tha 0.. so ,the first inequality holds true ✓ for second , x² will never be greater than x-4 because x-4 wil be > 0 when x > 4 , and then the value of x² will always be greater than 0 so, it will not hold true.. hence no solution is there.. for this inequality. wrong answer |
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