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20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide and8.0 g magnesium oxide. What will be the percentage of purity of magnesium carbonate in the sample?

Answer» <html><body><p>60<br/>84<br/>75<br/>96</p>Solution :`MgCO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) overset(Delta)(to) MgO + CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)<a href="https://interviewquestions.tuteehub.com/tag/uarr-3241817" style="font-weight:bold;" target="_blank" title="Click to know more about UARR">UARR</a>` <br/>84 g of `MgCO_(3)`gives 40 g of MgO. (100% purity) <br/>20g of `MgCO_(3)` will give `=(40xx20)/84=9.52g` <br/>9.52g of MgO is given by 100% pure `MgCO_(3)`. <br/>8.0 g of MgO will be given by=`(100xx8)/9.52=84.03%`</body></html>


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