1.

20.0 g. of a magnesium carbonate sampledecomposes on heating to give carbondioxide and 8.0 g magnesium oxide. Whatwill be the percentage purity of magnesiumcarbonate in the sample? (Atomic weight ofMg 24)

Answer»

MgCO₃ ⇒ MgO + CO₂84g 40gy g 8 g (y is variable used)

y=(84 x 8)/40 = 16.8 g

Percentage purity of MgCO₃ = (16.8 x 100)/20=84%



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