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20.0 kg of `N_(2)(g)` and 3.0 kg of `H_(2)(g)` are mixed to produce `NH_(3)(g)`. The amount of `NH_(3)(g)` formed isA. 17 kgB. 34 kgC. 20 kgD. 3 kg |
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Answer» Correct Answer - A `underset(28" g")(N_(2)) + underset(6" g")(3H_(2)) rarr underset(34" g")(2NH_(3))` Limiting reactant is `H_(2)` Weight of `NH_(3)` obtained from `6xx 10^(-3) ` kg of `H_(2)` `= 34xx 10^(-3) ` kg `therefore` Weight of `NH_(3)` obtained from 3 kh of `H_(2)` `= (34xx 10^(-3))/(6xx 10^(-3)) xx 3 ` = 17 kg `NH_(3)` |
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