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20. Assuming that a person of normal sight can read print at such a distance that the letters subtendan angle of 5’ at his eye, find what is the height of the letters that can read at a distance of 12meters.

Answer»

Convert 5` into degrees = 5/ 60 degrees

Now replace it in the equation 
tan (5/60) = PQ/12

PQ = 12 * tan (1/12)
= 12* 0.00145
= 0.0174 m =1.7cm



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