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20 g of a non-volatile solute is added to 500 g of solvent. Freezing point of solvent `= 5.48^(@)C` and solution `= 4.47^(@)C. K_(f)=1.93^(@)//m`. Molecular mas of the solute isA. `72.2`B. `76.4`C. `73.2`D. `70.6` |
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Answer» Correct Answer - B `Delta T_(f)=5.48-4.47=1.01` `Delta T_(f)=K_(f)xx m` `rArr 1.01=1.93xx(20)/(M)xx(1000)/(500)rArr M=76.4`. |
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