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20 gm sample containing Mg. is treated with excess of 2M HCl. As a result 11.2 litre of `H_(2)` gas at NTP was evolved. Find % purity of Mg in sampleA. 0.6B. 0.3C. 0.75D. 0.72 |
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Answer» `Mg+2HClrarrMgCl_(2)+H_(2)` `n_(Mg)=n_(H_(2))=(11.2)/(22.4)=(1)/(2)` `w_(Mg)=12gm` `% "purity"=(12)/(20)xx100=60` |
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