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20 J work is required to stretch a spring through 0.1 m. Find the force constant of the spring If the spring is further stretched through 0.1 m, calculate work done

Answer» <html><body><p></p>Solution :P.E. of spring when stretched through a distance 0.1 m <br/> `<a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a>=W.D.=1/2K.x^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)=<a href="https://interviewquestions.tuteehub.com/tag/20j-292958" style="font-weight:bold;" target="_blank" title="Click to know more about 20J">20J</a> or k=4000N/m` <br/> when spring is fruther stretched through 0.1 m, then P.E. will be: <br/> `U^(.)=1/2k(0.2)^(2)=80J` <br/> `W.D.=U^(.)-U=80-20=60J`</body></html>


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