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20 J work is required to stretch a spring through 0.1 m. Find the force constant of the spring If the spring is further stretched through 0.1 m, calculate work done |
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Answer» Solution :P.E. of spring when stretched through a distance 0.1 m `U=W.D.=1/2K.x^(2)=20J or k=4000N/m` when spring is fruther stretched through 0.1 m, then P.E. will be: `U^(.)=1/2k(0.2)^(2)=80J` `W.D.=U^(.)-U=80-20=60J` |
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