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`20 mL of 0.2MAl_(2)(SO_(4))_(3)` mixed with `20 mL` of `0.6M BaCl_(2)`. Calculate the concentration of each ion in solution. |
Answer» `Al_(2) (SO_(4))_(3) + BaCl_(3) + BaCl_(2) rarr BaSO_(4) darr + AlCl_(3)` mEq before `20 xx 0.2 xx 6` `20 xx 0.6 xx 2` 0 0 mEq after 0 0 24 24 mixing mEq `= M xx V` (in `mL`) `M xx` Valency `:. [Al^(3+)] = (24)/(40 xx 3) = 0.2 M` Total volume `= 20 + 20 = 40 mL` `[Cl^(ɵ) = 0.6 M` No concentration of `Ba^(2+)` or `SI_(4)^(2-)` in the solution since `BaSO_(4)` gets precipitated. |
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