20 ml of the solution containg Na_(2)CO_(3) and NaHCO_(3) is titrated with 0.1MHCI using Phenolphthalein indicator the end point was 10ml. 20ml of the same solution is titrated with 0.1M HCI, the end point was 25ml with Methylorange indicaor from the begining. NaHCO_(3)+HCl rarr NaCl +H_(2)O +CO_(2) Na_(2)CO_(3)+2HCl rarr 2NaCl +CO_(2) +H_(2)O What is amount of NaHCO_(3) present in 1 litre of solution

20 ml of the solution containg Na_(2)CO_(3) and NaHCO_(3) is titrated

1.	20 ml of the solution containg Na_(2)CO_(3) and NaHCO_(3) is titrated with 0.1MHCI using Phenolphthalein indicator the end point was 10ml. 20ml of the same solution is titrated with 0.1M HCI, the end point was 25ml with Methylorange indicaor from the begining. NaHCO_(3)+HCl rarr NaCl +H_(2)O +CO_(2) Na_(2)CO_(3)+2HCl rarr 2NaCl +CO_(2) +H_(2)O What is amount of NaHCO_(3) present in 1 litre of solution
Answer» <html><body><p>`2.1g`<br/>`1.05g`<br/>`8.1g`<br/>`0.844g`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Using <a href="https://interviewquestions.tuteehub.com/tag/methyl-1095247" style="font-weight:bold;" target="_blank" title="Click to know more about METHYL">METHYL</a> orange, <br/> `x +y = 25 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 0.1 = 2.5, y = 2.5 - 2 = 0.5` <br/> Wt of `NaHCO_(3)` in 20ml `=(0.5)/(1000) xx <a href="https://interviewquestions.tuteehub.com/tag/84-339262" style="font-weight:bold;" target="_blank" title="Click to know more about 84">84</a> = 0.042g` <br/> wt of `NaHCO_(3)` in 1 lit `=(0.042)/(20) xx 1000 = 2.1g`</body></html>