20. The present age of a man is twice that of hisson. Eight years henc

1.	20. The present age of a man is twice that of hisson. Eight years hence, their ages will be inthe ratio 7:4. Find their present ages.
Answer» Let present age of son = xPresent age of father = 2x After 8 yearsAge of son = x + 8Age of father = 2x + 8 Given (2x+8)/(x+8) = 7/4 4(2x+8) = 7(x + 8) 8x + 32 = 7x + 56 x = 56-32 = 24 Present age of father = 2x = 2*24 = 48 yrsPresent age of son = x = 24 yrs

20. The present age of a man is twice that of hisson. Eight years hence, their ages will be inthe ratio 7:4. Find their present ages.

Answer»

Let present age of son = xPresent age of father = 2x

After 8 yearsAge of son = x + 8Age of father = 2x + 8

Given (2x+8)/(x+8) = 7/4 4(2x+8) = 7(x + 8) 8x + 32 = 7x + 56 x = 56-32 = 24

Present age of father = 2x = 2*24 = 48 yrsPresent age of son = x = 24 yrs