200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`A. `31011g mol^(-1)`B. `61038 g mol^(-1)`C. `51022 g mol^(-1)`D. `122044 g mol^(-1)`

200 mL of an aqueous solution of a protein contains its 1.26g. The osm

1.	200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`A. `31011g mol^(-1)`B. `61038 g mol^(-1)`C. `51022 g mol^(-1)`D. `122044 g mol^(-1)`
Answer» Correct Answer - B `pi=CRT=(wt xx 1000)/(GMM xx V)RT` `2.57xx10^(-3)=(1.26xx1000)/(GMM xx200)xx0.083xx300` GMM = 61038 g

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200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`A. `31011g mol^(-1)`B. `61038 g mol^(-1)`C. `51022 g mol^(-1)`D. `122044 g mol^(-1)`

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