200g of a solid ball at 20^(@)C is dropped in an equal amount of water at 80^(@)C. The resulting temperature is 60^(@)C. This means that specific heat of solid is

200g of a solid ball at 20^(@)C is dropped in an equal amount of water

1.	200g of a solid ball at 20^(@)C is dropped in an equal amount of water at 80^(@)C. The resulting temperature is 60^(@)C. This means that specific heat of solid is
Answer» One fourth of water one HALF of water twice of water four times of water Solution :HEAT lost by the water, `Q_(1) = 200 XX s_(w) xx (80-60)` Heat GAINED by the solid, `Q_(2) = 200 xx s_(s) xx (60-20)` According to the principle of calorimetry `Q_(1) = Q_(2)` `:. 200 xx s_(w) xx (80 -60) = 200 xx s_(w) xx (60-20)` or `s_(s) = (1)/(2) s_(w)`