200ml decimolar H2SO4 and 300ml decimolar HCl mixture is treated with M/5 NaOH solution. For complete neutralization of the mixture, the volume of NaOH needed is (1) 400ml (2) 250ml (3) 350ml (4) 100ml

200ml decimolar H2SO4 and 300ml decimolar HCl mixture is treated with

1.	200ml decimolar H2SO4 and 300ml decimolar HCl mixture is treated with M/5 NaOH solution. For complete neutralization of the mixture, the volume of NaOH needed is (1) 400ml (2) 250ml (3) 350ml (4) 100ml
Answer» 3) 350mlExplanation:Equivalence of ACIDIC solution= Equivalence of BASIC solutionN₁V₁n₁+N₂V₂n₂=N₃V₃n₃n=n-factorN=normalityV=volume1,2 and 3 subscript stands for H₂SO₄, HCl and NaOH respectively(2)(0.2)(0.1)+(0.1)(1)(0.3)=(0.2)(V)(1) V=0.07/0.3=0.350L=350mlHope this answer helped you, if so PLEASE mark as BRAINLIEST :)