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20mL of solution of 0.1M acetic acid is divided into two equal parts and kept in two beakers separately. To one beaker 0mL of 0.05M NaOH. Two hydrogen the other 10 mL of 0.025 M NaOH. Two hydrogen electrodes are placed in the two solutions which are linked through a salt-bridge. what would be the measured emf?A. 59mVB. 28mVC. 14mVD. 33mV |
Answer» Correct Answer - b | |