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21. A first order reaction takes 40 min for 30% decomposition. Calculate t1/2 for first order reaction ((log 7 = 0.8451, log 10 = 1)​

Answer»

77.7 minutes is the answerExplanation:LET a M be the initial concentration. After 40 minutes, the concentration is a−30a/ 100  =0.70a. k=  2.303/t log [A])  − / [A]k= 2.303/40  log a/ 0.70a k=8.92×10^−3 /min The half life PERIOD, t  1/2  = 0.693/k= 0.693/8.92×10 ^-3/min=77.7 MINUTE hope this HELPS u



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