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210 If sides of two similar triangles are in the ratio 4: 9. Find the areas of these triangles are in the ratio? |
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Answer» so area of these triangle is =(4\9)²=16\81=16:81 is the right answer 16:81 is the correct answer area of 1st ∆/area of 2nd ∆= (1st ∆ side)^2/(2nd ∆ side)^2let sides are 4x and 9x = (4x)^2/(9x)^2 =16x^2/81x^2 = 16/811st ∆ area : 2nd ∆ area = 16 : 81 |
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