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22.22 gram of urea was dissolved in 300 grams of water. Calculate the number of moles of urea and molality of the urea solution. (Given : Molar mass of urea = 60 gram `mol^(-1)`) |
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Answer» Given, Mass of urea = 22.22 gram Mass of water = 300 gram `therefore` No. of mole of urea `= ("Mass of urea")/("Molar mass of urea")` `=(22.22)/(60)=0.370` moles Molality (m) = `("Mole of urea")/("Mass of water")xx1000` `=(0.370)/(300)xx1000` Molality (m) = 1.23 moles `kg^(-1)` . |
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