22. 6.025 x 1020 molecules of acetic acid are present in500 ml of its solution. The concentration of solution is

22. 6.025 x 1020 molecules of acetic acid are present in500 ml of its

1.	22. 6.025 x 1020 molecules of acetic acid are present in500 ml of its solution. The concentration of solution is
Answer» no. of MOLE= 6.025x10^20/6.022x10^23 concentration=no. of mole x1000/500