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22: Find the zeros of the puyum23. Solve: 3x + 7y - 11 and 7x -y + 9 = 0 by elimination method.an attitude of equitatal ABC

Answer»

3x+7y=11—(i)7x-y=-9—(ii)multiplying (i) by 7 and (ii) by 3 we get21x+49y=7721x-3y=-27—————by subtracting we get52y=104y=104/52y=2substituting the value of y=2 in (i) we get3x+7(2)=113x=11-143x=-3x=-3/3x=-1therefore x=-1 and y=2

x= -1 and y= 2 is correct answer

let,3x+7y=11........eqn17x-y+9=0......eqn2

By multiplying eqn2 with 7 we get 49x-7y+63=0.....eqn2

Eliminate eqn1 and eqn23x+7y-11=049x-7y+9=052x. -2=052x=2 x=2/52 x=1/26Put the value of x in eqn1 3(1/26)+7y=11



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