1.

22 g of CO2 contains molecules of CO2 (a) 6.023 x 1023 (b) 6.023 x 1023 (c) 3.0115 x 1023 (d) 3.0115 x 1023

Answer»

(c) 3.0115 x 1023 

44 g of CO2 contains 6.023 x 1023 molecules. 

∴ 22 g of CO2 will contain = \(\frac{6.023 \times10^{23}}{44}\)x 22 

= 3.0115 x 1023



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