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`224 mL` of a triatomic gas weights `1 g at 273K` and `1 atm`. The mass of one atom of this gas is:A. `8*30xx10^(-23) g`B. `2*08xx10^(-23)` gC. `5.53xx10^(-23)` gD. `6.24xx10^(-23)` g |
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Answer» Correct Answer - C 224 mL of gas `X_(3)` has mass = 1 g `:.` 22,400 mL of gas has mass `=(1)/(224)xx22,400 = 100g` Mass of one atom `= (100)/(3xx6.02xx10^(23))` `= (16.61xx10^(-23))/(3)g = 5.53xx10^(-23)g` |
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