23.An element, X has the following isotopiccomposition:200X :90% 199X

1.	23.An element, X has the following isotopiccomposition:200X :90% 199X :8.0% 202X. 2.0%The weighted average atomic mass of thenaturally occurring element X is closest to(A) 201 u(C) 199 uIAIPMT 2007](B) 202 u(D) 200 u
Answer» The weighted Average atomic mass of element [x]=0.9(200)+0.08(199)+0.02(202)=180+15.92+4.04=199.96amu≈200 amu The weighted average atomic mass of the naturally occurring element X is closest to 200 amu

23.An element, X has the following isotopiccomposition:200X :90% 199X :8.0% 202X. 2.0%The weighted average atomic mass of thenaturally occurring element X is closest to(A) 201 u(C) 199 uIAIPMT 2007](B) 202 u(D) 200 u

Answer»

The weighted Average atomic mass of element [x]=0.9(200)+0.08(199)+0.02(202)=180+15.92+4.04=199.96amu≈200 amu

The weighted average atomic mass of the naturally occurring element X is closest to 200 amu