23. HVml of the vapours of substance at NTP weight Wg. Then mol w. of – InterviewSolution

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1.

23. HVml of the vapours of substance at NTP weight Wg. Then mol w. of substance ia(3) N-V) 22400 W1(1)(WM r22400(2)x224Vx 22400

Answer»

Mole = V / 22400

Mole = Weight / Molecular weight

So, V / 22400 = W / Molecular weight

Molecular weight = (W / V ) * 22400

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