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√23 is a rational or irrational no.

Answer» Irrational
Assume it was rational then\xa0√23√23\xa0= a/b,\xa0where a, b are integers,\xa0and\xa0therefore 23 = a²/b².\xa0So a² = 23b².\xa0Now\xa0√a² = a = an integer,\xa0and\xa0therefore\xa0√23b²\xa0= integer.\xa0√23b²= b*√23√23\xa0is not an integer, so the assumption was wrong.\xa0Therefore\xa0√23\xa0is not rational.


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