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23. The least number which when divided by6, 15 and 18 leave remainder 5 in eachcase, is |
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Answer» L.C.M. of 6, 15 and 18 2 | 6, 15 ,183 | 3, 15, 93 | 1, 5, 35 | 1,5, 1 = 2 x 3 x 3 x 5 = 90 Therefore the required number = 90 + 5 = 95 L.C.M of 6,15 and 18 2l6, 15,183l3, 15,93l1, 5,35l1, 5,1=2×3×3×5so, the correct answer =90+5=95 |
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