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24. a) Calculate the energy transferred when 2 A current Dows through a 10 resistor for 30 minutes​

Answer»

The Energy transferred is 72,000 joules.Explanation:As POWER (P) = IV and V=IR=> P = I (SQUARE) × RHence power = 4 × 10 = 40 wattWe also know that P = E / tThus E = P × t = 40 × 1/2 watthour= 20 watthour or 0.02 KILOWATTHOUR (unit)To FIND the energy in wattsec (joules)convert time into seconds which EQUALS to 30 × 60 = 1800 secTHUS ENERGY TRANSFERRED = 40 × 1800 = 72,000 wattsec (joules)



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