248 gm mixture containing Li2CO3 & CaCO3 on strong heating produces CO2(g), which exerts 3 atm pressure in a container of volume 24 L at temperature 27° C. The simplest mole ratio of Li2CO3 and CaCo3 in the mixture is x: 1. The value of x'is: [Given that R=0.08L-atm/k-mole] [Atomic weight of Li = 7, Ca = 40]

248 gm mixture containing Li2CO3 & CaCO3 on strong heating produces CO

1.	248 gm mixture containing Li2CO3 & CaCO3 on strong heating produces CO2(g), which exerts 3 atm pressure in a container of volume 24 L at temperature 27° C. The simplest mole ratio of Li2CO3 and CaCo3 in the mixture is x: 1. The value of x'is: [Given that R=0.08L-atm/k-mole] [Atomic weight of Li = 7, Ca = 40]
Answer» CACO 3 (s)⇌CaO(s)+CO 2 (G)K p =p CO 2 =3.9×10 −2 atmLet the NUMBER of moles of CO 2 formed =nn= RTp CO 2 ×V = 0.082Latm/mol/K×1000K3.9×10 −2 atm×0.654L =3.11×10 −4 molThe amount of CaO(s) formed will also be 3.11×10 −4 molThe molecular WEIGHT of CaO=56g/molHence, the mass of CaO formed =3.11×10 −4 mol×56g/mol=0.0174g