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25.3 g of sodium carbonate, `Na_(2)CO_(3)` is dissolved in enough water to make 250 mL of solution. If sodium carbonate dissociates completely, molar concentration of sodium ions, `Na^(+)` and carbonate ions, `CO_(3)^(2-)` are respectively (Molar mass of `NaCO_(3)=106g mol^(-1)`)A. 0.477 M and 0.477 MB. 0.955 M and 1.910 MC. 1.910 M and 0.955 MD. 1.90 M and 1.910 M |
Answer» Correct Answer - C Molarity `(M)=(wt)/(mol.wt.)(1000)/("vol(in ml)")` `=(25.3)/(106)xx(1000)/(250)=0.955` mol/L of `Na_(2)CO_(3)` and `Na_(2)CO_(3)rarr 2Na^(+)+CO_(3)^(-2)` therefore `[Na^(+)]=2xx0.955=1.910 M` `[CO_(3)^(-2)]=0.955 M` |
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