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25. Manganese forms non-stoichiometric oxides having the general formula Mno .The value of x for the compound that analyze64% Mn-(3) 2(4) 1.93(2) 1.83NLIHpO cotin 30 409% mass nercent of nitrogen. What is the mass ratio of the two |
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Answer» molar mass of Mn = 54 now %Mn = 64% = 0.64suppose x atoms O are there.. so mass will be (x)*16 = 16x now total mass of Mn(O)x = 54+16x and for % the equation is 54/54+16x = 0.64 => 54 = 0.64*54 +0.64*16x => 54(1-0.64) = 10.24x or x = 54*0.36/10.24 = 1.89 option D. |
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