25 mL of a gaseous hydrocarbon is mixed with 150mL of oxygen in an eudiometer. After sparking and cooling back the mixture is passed through alkaline pyrogallol. The volume loss surffered in pyrogallol is 25mL. Calculate the molecular weight of hydrocarbon.

25 mL of a gaseous hydrocarbon is mixed with 150mL of oxygen in an eud

1.	25 mL of a gaseous hydrocarbon is mixed with 150mL of oxygen in an eudiometer. After sparking and cooling back the mixture is passed through alkaline pyrogallol. The volume loss surffered in pyrogallol is 25mL. Calculate the molecular weight of hydrocarbon.
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of oxygen taken = 150mL <br/> Volume of unreacted oxygen, absorbed in pyrogallol = <a href="https://interviewquestions.tuteehub.com/tag/25ml-298126" style="font-weight:bold;" target="_blank" title="Click to know more about 25ML">25ML</a> <br/> Ratio of volumes of <a href="https://interviewquestions.tuteehub.com/tag/hydrocarbon-1034072" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROCARBON">HYDROCARBON</a> and oxygen = 25mL : 125mL = 1:5 <br/> One volume of hydrocarbon consumes five volumes of oxygen for combustion. <br/> The gaseous hydrocarbon is `C_(3)H_(8)` <br/> Molecular weight of the gaseous hydrocarbon = 44</body></html>