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25 ml of a solution containing HCl and `H_(2)SO_(4)` required 10 ml of 1 M NaOH solution for complete neutralization. 20 ml of the same acid mixture on being treated with excess of `AgNO_(3)` gives Report your answer as `(x+y)xx1000.` |
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Answer» Let molarity of HCl is x and `H_(2)SO_(4)` is y `{:( m" mole " " m mole "),( x xx25" "+" "2yxx25=10xx1),(" "underbrace(" ")),(" " m" mole of " [H^(+)]):}` Applying POAC Applying POAC `(20xxx)/(1000)=(0.1435)/(143.5)=10^(-3)` `x=(1)/(20)=0.05M` `y=(8.75)/(50)=0.175M` ` therefore(x+y)xx1000=(0.05+0.175)xx1000=225` |
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