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25 mL of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a titre value of 35 mL. The molarity of barium hydroxide solution was :A. 0.28B. 0.35C. 0.07D. 0.1 |
Answer» Correct Answer - C `underset("1 mol")(Ba(OH)_(2))+underset("2 mol")(2HCl)rarrBaCl_(2)+2H_(2)O` No. of moles of `HCl=(("0.1 mol"^(-1)))/(("1L"))xx("0.035L")` `=3.5xx10^(-3)` mol No. of moles of `Ba(OH)_(2)=(3.5xx10^(-3))/(2)` `=1.75xx10^(-3)` mol Molarity of `Ba(OH)_(2)` solution `= ("No. of moles of Ba"("OH")_(2))/("Volume of solution in litres")` `=((1.75xx10^(-3)"mol"))/(("0.025 L"))=0.07"mol L"^(-1)` `=0.07M`. |
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