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25 msThe time takenv by current to reach theEquation of alternating current is given by 10/2sin 100ntroot mean square value from t 0 i8 e ahen the value of ls(2) 2501200(4) 800To(3)200(5 n the AC direuit the current is expressed as 100 sin 200rl In this circuit the current rises from zero topeak value in time12)3004003)200100

Answer» 25 msThe time takenv by current to reach theEquation of alternating current is given by 10/2sin 100ntroot mean square value from t 0 i8 e ahen the value of ls(2) 2501200(4) 800To(3)200(5 n the AC direuit the current is expressed as 100 sin 200rl In this circuit the current rises from zero topeak value in time12)3004003)200100


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