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250 gram of D-Glucose solution contain 10.8% carbon by weight. Find molality of solution. [Report your answer to nearest value](1) 1.03 m(2) 20.55(3) 0.05(4) 4.03 |
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Answer» Correct option is (2) 20.55 Glucose ⇒ C6H12O6 [GMM = 180] Mass of carbon (in 250 gram solution) = \(\left[\frac{250 \times 10.8}{100}\right]\) ∴ 72 gram of carbon in total mass of glucose (180) \(\frac{250 \times 10.8}{100}\) Gram carbon present in = \(\frac{180}{72}\times\frac{250 \times 10.8}{100}\) = 67.5 gram Mass of solvent = (250 - 67.5) = 182.5 gram Molality = \(\left(\frac{67.5\times1000}{180 \times182.5}\right) = 20.55\) |
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