InterviewSolution
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InterviewSolution
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`25ml` of `0.017H_(2)SO_(4)` in strongly acidic medium required `16.9mL` of `0.01M KMnO_(4)` and in neutral medium required `28.6mL` of `0.01MKMnO_(4)` for complete conversion fo `SO_(3)^(2-)` to `SO_(4)^(2-)` .Assign the oxidation no of `Mn` in the product formed in each case. |
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Answer» `SO_(3)^(2-)rarrSO_(4)^(2-)` `S^(4+)rarrS^(6+)+2e` `therefore ` Valence factor of `SO_(3)=2` In acid medium: Meq.of `SO_(3)^(2-)="Meq.of" MnO_(4)^(-)` `25xx0.017xx2=16.9xx0.01xxn_(1)` `therefore n_(1)=5` `therefore Mn^(7+)+5erarrMn^(4+)` In neutral medium: Meq.of `SO_(3)^(2-)=` Meq.of `MnO_(4)^(-)` `25xx0.017xx2=28.6xx0.01xxn_(2)` `therefore n_(2)=3` ltbr. `therefore Mn^(7+)+3e rarrMn^(4+)` |
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