1.

26. Calculate Kc for the reversible process given below ifK167 and T 800° C(a) 1.95(c) 1.89Caco, (s)-CaO(s) + CO2 (g ) [WB JEE)(b) 1.85(d) 1.60

Answer»

Using the formula

Kp = Kc(RT)^(∆n)

here ∆n = 1 , Kp = 167 , R = 0.083 and T = (800+273)k,

so , 167 = Kc(0.083*1037)¹ => 167 = Kc *(89.06) => Kc = 167/89.06 = 1.875

option B


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